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The sum of the digits of a two-digit number is 15. The number obtained by interchanging the digits exceeds the given number by 9. Find the number.

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Let the number be 10x + y. Then x + y = 15 and (10y + x) − (10x + y) = 9, which simplifies to y − x = 1. Adding both equations gives 2y = 16, so y = 8, x = 7. The number is 78.

NCERT Solution for Class 9 Ganita Manjari Part 2 chapter 13 question answer

NCERT Solution for Ganita Manjari Part 2 chapter 13 Two Variables, One Line solutions

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1 Answer

  1. Let the tens digit be x and the units digit be y, making the original number 10x + y. The sum of digits gives x + y = 15. Reversing the digits gives 10y + x. The difference condition (10y + x) − (10x + y) = 9 reduces to 9y − 9x = 9 or y − x = 1. Adding x + y = 15 and y − x = 1 yields 2y = 16, giving y = 8 and x = 7. The number is 78.

     

    For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 13 Two Variables, One Line Question Answer (2026-27)

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-13/

     

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