NCERT Solutions for Class 8 Mathematics Chapter 11
Important NCERT Questions
Mensuration Chapter 8 Exercise 11
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 3
The shape of a garden is rectangular in the middle and semi-circular at the ends as shown in the diagram. Find the area and the perimeter of this garden [Length of rectangle is 20 – (3.5 + 3.5 meters]
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Given: Total length = 20 m
Diameter of semi circle = 7 m
∴ Radius of semi circle = 7/2=3.5m
Length of rectangular field = 20 – (3.5 + 3.5) = 20 – 7 = 13 m
Breadth of the rectangular field = 7 m
∴ Area of rectangular field = l X b = 13 x 7 = 91 m²
Area of two semi circles = 2×1/2(πr²) = 2×1/2×22/7×3.5×3.5=38.5m²
Area of garden = 91 + 38.5 = 129.5 m²
Now Perimeter of two semi circles = 2xπr=2×22/7×3.5=22 m
And Perimeter of garden = 22 + 13 + 13 = 48 m
Class 8 Maths Chapter 11 Exercise 11.1 Solution in Video
for more answers vist to:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-11/