Asked: 2025-02-22T05:44:40+00:002025-02-22T05:44:40+00:00In: Class 10 Maths
The ratio of the outer and inner perimeters of a circular path is 23:22. If the path is 5 metres wide, the diameter of the inner circle
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Enhance your Class 10th Maths preparation with NCERT solutions and MCQ-based questions from Chapter 11: Areas Related to Circles. Solve exercise questions, short-answer problems and detailed explanations to master concepts like areas of sectors, segments and combinations of plane figures. These resources align with the CBSE syllabus, ensuring effective exam readiness. Regular practice will improve your problem-solving skills and boost your confidence for board exams. Access step-by-step solutions and revision notes tailored to simplify complex ideas and help students succeed. Focus on understanding the formulas and their real-life applications to strengthen your foundation. Begin practicing today to excel in this chapter and achieve excellent results in exams. Start now!
Given:
– Ratio of outer to inner perimeter = 23:22,
– Width of path = 5 m.
From ratio: R/r = 23/22 ⇒ R = (23/22)r.
Width: R – r = 5 ⇒ (23/22)r – r = 5.
Simplify:
(1/22)r = 5 ⇒ r = 5 × 22 = 110 m.
Diameter of inner circle = 2r = 2 × 110 = 220 m.
This question related to Chapter 11 Mathematics Class 10th NCERT. From the Chapter 11 Area related to Circle. Give answer according to your understanding.
Given:
– Ratio of outer to inner perimeter = 23:22,
– Width of path = 5 m.
From ratio: R/r = 23/22 ⇒ R = (23/22)r.
Width: R – r = 5 ⇒ (23/22)r – r = 5.
Simplify:
(1/22)r = 5 ⇒ r = 5 × 22 = 110 m.
Diameter of inner circle = 2r = 2 × 110 = 220 m.
This question related to Chapter 11 Mathematics Class 10th NCERT. From the Chapter 11 Area related to Circle. Give answer according to your understanding.
Given:
– Ratio of outer to inner perimeter = 23:22,
– Width of path = 5 m.
From ratio: R/r = 23/22 ⇒ R = (23/22)r.
Width: R – r = 5 ⇒ (23/22)r – r = 5.
Simplify:
(1/22)r = 5 ⇒ r = 5 × 22 = 110 m.
Diameter of inner circle = 2r = 2 × 110 = 220 m.
This question related to Chapter 11 Mathematics Class 10th NCERT. From the Chapter 11 Area related to Circle. Give answer according to your understanding.
Given:
– Ratio of outer to inner perimeter = 23:22,
– Width of path = 5 m.
From ratio: R/r = 23/22 ⇒ R = (23/22)r.
Width: R – r = 5 ⇒ (23/22)r – r = 5.
Simplify:
(1/22)r = 5 ⇒ r = 5 × 22 = 110 m.
Diameter of inner circle = 2r = 2 × 110 = 220 m.
This question related to Chapter 11 Mathematics Class 10th NCERT. From the Chapter 11 Area related to Circle. Give answer according to your understanding.
For more please visit here:
https://www.tiwariacademy.in/ncert-solutions/class-10/maths/
Given:
– Ratio of outer to inner perimeter = 23:22,
– Width of path = 5 m.
From ratio: R/r = 23/22 ⇒ R = (23/22)r.
Width: R – r = 5 ⇒ (23/22)r – r = 5.
Simplify:
(1/22)r = 5 ⇒ r = 5 × 22 = 110 m.
Diameter of inner circle = 2r = 2 × 110 = 220 m.
This question related to Chapter 11 Mathematics Class 10th NCERT. From the Chapter 11 Area related to Circle. Give answer according to your understanding.
For more please visit here:
https://www.tiwariacademy.in/ncert-solutions/class-10/maths/
Given:
– Ratio of outer to inner perimeter = 23:22,
– Width of path = 5 m.
From ratio: R/r = 23/22 ⇒ R = (23/22)r.
Width: R – r = 5 ⇒ (23/22)r – r = 5.
Simplify:
(1/22)r = 5 ⇒ r = 5 × 22 = 110 m.
Diameter of inner circle = 2r = 2 × 110 = 220 m.
This question related to Chapter 11 Mathematics Class 10th NCERT. From the Chapter 11 Area related to Circle. Give answer according to your understanding.
For more please visit here:
https://www.tiwariacademy.in/ncert-solutions/class-10/maths/