Increasing the radius by 10% makes the new radius 1.1r. The new volume is proportional to (1.1r)³ = 1.331r³, representing a 0.331 or 33.1% increase over the original volume.
Ganita Manjari Part 2 Class 9 Chapter 14 Step by Step Solutions
Class 9 Chapter 14 Math of Space Surface Area and Volume (Ganita Manjari 2) Solutions
Let the original radius of the sphere be r, so its original volume is V = (4/3)πr³. When the radius increases by 10%, the new radius becomes r’ = 1.1r. The new volume is V’ = (4/3)π(1.1r)³ = 1.331 × (4/3)πr³ = 1.331V. The fractional increase is (V’ − V) / V = 0.331, which corresponds to a 33.1% increase in volume.
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
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