Your answer is awaiting moderation.
Radius of first circle (r₁) = 19 cm,
Radius of second circle (r₂) = 9 cm
Let, the radius of the third circle = r
Circumference of the first circle = 2πr₁ = 2π (19) = 38π
Circumference of the second circle = 2πr₂ = 2π (9) = 18π
Circumference of the third circle = 2πr
According to question,
Circumference of the third circle = Circumference of the first circle + Circumference of the second circle
⇒ 2πr = 38π + 18π ⇒ 2πr = 56π ⇒ r = 56π/2π = 28
Hence, the radius of the circle, which has circumference equal to the sum of the circumferences of the two circles, is 28 cm.

Here is the Video Solution of the above question ✔