annu10
  • 1
Poll

The quadratic equation whose roots are 5 and -2 is:

  • 1

Poll Results

50%x² - 3x - 10 = 0 ( 2 voters )
0%x² + 3x - 10 = 0
0%x² - 3x + 10 = 0
50%x² + 3x + 10 = 0 ( 2 voters )
Based On 4 Votes

Participate in Poll, Choose Your Answer.

A quadratic equation has the standard form ax² + bx + c = 0 where a b and c are numbers and a is not equal to 0. We can solve it using the quadratic formula -b ± √(b² – 4ac) divided by 2a to find the x-values that make the equation true.

A quadratic equation follows the standard form ax² + bx + c = 0 where a b and c represent constant terms and a cannot be zero. Students learn to solve these equations using factorization square completion and quadratic formula methods. Solutions represent the x-values where the parabola intersects the x-axis. Real-world applications include projectile motion calculating area and analyzing profit-loss scenarios.
The chapter covers finding roots nature of roots relationship between discriminant and roots and applications in daily life. Students also learn graphical representation to visualize solutions as x-intercepts of parabolas.

Share

1 Answer

  1. The quadratic equation whose roots are 5 and -2 is: x² – 3x – 10 = 0

    Let’s verify:
    If α = 5 and β = -2 are roots then:
    Sum of roots = -(coefficient of x)/coefficient of x²
    α + β = -b/a = 3

    Product of roots = constant term/coefficient of x²
    α × β = c/a = -10

    Therefore x² – 3x – 10 = 0 is correct as:
    – coefficient of x: -(α + β) = -3
    – constant term: α × β = -10

    Hence option x² – 3x – 10 = 0 is correct.

    Click here for more:
    https://www.tiwariacademy.in/ncert-solutions/class-10/maths/

    • 14
Leave an answer

Leave an answer

Browse