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Ashok0210
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Asked: 2021-04-27T07:04:04+00:00 In:

The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?

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Class 12 Physics
CBSE and UP Board
Dual Nature of Radiation and Matter
Chapter-11 Exercise 11.3
NCERT Solutions for Class 12 Physics Chapter 11 Question-3

2020-2021cbse and up boardclass 12 chapter-11 physicsclass 12 physicsncert class 12 dual nature of radiation and matter
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      Photoelectric cut-off voltage, Vo = 1.5 V

      The maximum kinetic energy of the emitted photoelectrons is given as:

      Ke=eV0

      Where, e = Charge on an electron = 1.6 x 10-19 C

      Therefore, Ke = 1.6 x 10-19 x 1.5

      = 2.4 x 10-19 J

      Therefore, the maximum kinetic energy of the photoelectrons emitted in the given experiment is 2.4 x 10-19J.

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