Home/ Questions/Q 478115
Next
In Process
Gopal001 Das
  • 1
Poll
Asked: 2025-03-07T09:47:23+00:00 In:

The mean free path of electrons in a metal is 4 X 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in the units V/m,

  • 1

Poll Results

0%(a) 5 × 10⁻¹¹
40%(b) 8 × 10⁻¹¹ ( 2 voters )
40%(c) 5 × 10⁷ ( 2 voters )
20%(d) 8 × 10⁷ ( 1 voter )
Based On 5 Votes

Participate in Poll, Choose Your Answer.

The energy gained by an electron in an electric field
E over a mean free path l is given by:
eEl = 2 eV
Solving for E:
E = 2 × 1.6 × 10⁻¹⁹ /4 × 10⁻⁸ = 8 × 10⁷ V/m
Thus, the correct answer is (d) 8 × 10⁷ V/m.
Class 12th Science Physics NCERT MCQ Questions
NCERT Books MCQ Questions Session 2024-2025.

class 12thmcqphysics
Share

    1 Answer

    1. The energy gained by an electron in an electric field E over a mean free path λ is given

      by:
      eEλ=2 eV
      Substituting e = 1.6 × 10⁻¹⁹ C and
      λ = 4 × 10 m:
      E = 2 1.6 × 10⁻¹⁹/4 × 10⁻⁸
      E = 8 × 10⁷ V/m
      Thus, the correct answer is (d) 8 × 10⁷ V/m.

      For more visit here:
      https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-3/

      • 47
    Leave an answer

    Leave an answer

    Browse