The word PEACE has 5 letters: P, E, A, C, E. (i) Letters P, E, C occur 4 times, giving probability 4 / 5 = 0.8. (ii) Non-E letters are P, A, C (3 letters), giving probability 3 / 5 = 0.6.
The letters of the word ‘PEACE’ are placed on cards. Leela draws a card without looking. (i) What is the probability that it is a P, E or C? (ii) What is the probability that it is not an E?
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Total letters in the word PEACE = 5, so total possible outcomes = 5.
(i) Favourable letters for ‘a P, E or C’ are P, E, C, E (1 P, 2 Es and 1 C).
Number of favourable outcomes = 1 + 2 + 1 = 4.
Probability(P, E or C) = 4 / 5 = 0.8 (or 80%).
(ii) Letters that are not E are P, A and C.
Number of favourable outcomes = 3.
Probability(not an E) = 3 / 5 = 0.6 (or 60%).
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 7 The Mathematics of Maybe: Introduction to Probability Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-7/