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The following distribution shows the daily pocket allowance of children of a locality.

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The mean pocket allowance is Rs 18. Find the missing frequency f.
NCERT Class 10 Math’s chapter 14 Statistics
Page No. 270
Exercise 14.1
Question No. 3

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1 Answer

  1. To find the class mark (xᵢ) for each interval, the folowing relation is used.
    xᵢ = (Upper limit + Lower limit)/2
    Given that the mean nocket allawance is ₹18 Taking 18 as.assured mean (a), dᵢ and fᵢdᵢ are calculated as follows:

    From the table, we obtain
    ∑fᵢ = 44 + f, ∑fᵢdᵢ = 2f – 40 and a = 18
    mean(X̄) = a + (∑fᵢdᵢ)/∑fᵢ ⇒ 18 = 18 + ((2F – 40)/(44 + F)) ⇒ 0 = (2F – 40)/(44 + f) ⇒ 2f – 40 = 0 ⇒ f = 20
    Hence, the value of missing frequency f is 20.

    See this video explanation 😮✌👇

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