The radius is half the diameter, so it is 13 cm. The perpendicular from the centre bisects the chord, giving half chord 12 cm. Hence, the distance is 5 cm.
The diameter of a circle is 26 cm. A chord of length 24 cm is drawn in the circle. Find the distance from the centre of the circle to the chord.
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The diameter of the circle is 26 cm, so its radius is 13 cm. The perpendicular from the centre to a chord bisects the chord. Therefore, half of the chord is 12 cm.
Using the right triangle:
Distance² = 13² – 12²
= 169 – 144
= 25
Therefore, distance = 5 cm.
Hence, the distance from the centre of the circle to the chord is 5 cm.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/