The current sensitivity of a galvanometer increases by 20%. If its resistance also increases by 25%, the voltage sensitivity will
Voltage sensitivity is given by
ls/R’ where I s
is current sensitivity. If current sensitivity increases by 20% and resistance by 25%, voltage sensitivity changes by 120/125 = 0.96, i.e., decreases by 4%.
The answer is (D) Decrease by 4%.
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The voltage sensitivity of a galvanometer is given by:
Voltage Sensitivity = Current Sensitivity/R
If current sensitivity increases by 20% and resistance increases by 25%, the net change in voltage sensitivity is:
1.2/1.25 = 0.96
This indicates a 4% decrease in voltage sensitivity.
Answer: (D) Decrease by 4%.
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