The base of an isosceles triangle is 24 cm and its area is 192 cm², then its perimeter is
Kickstart your journey in Class 9th Maths with NCERT solutions and MCQ-based questions from Chapter 10: Heron’s Formula. Solve exercise questions, short-answer problems and detailed explanations to understand how to calculate areas of triangles and quadrilaterals using semi-perimeter and Heron’s Formula. These resources align with the CBSE syllabus, ensuring complete exam readiness. Regular practice will sharpen your logical reasoning skills and prepare you for exams. Use step-by-step solutions and revision notes tailored to simplify learning. Begin practicing now to excel in exams.
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Base = 24 cm, Area = 192 cm²
Height = (2 × Area) / Base = (2 × 192) / 24 = 16 cm
Using Pythagorean theorem:
x² = (24/2)² + 16² = 12² + 16² = 144 + 256 = 400
x = √400 = 20 cm
Perimeter = 2x + Base = 2(20) + 24 = 64 cm
This question is based on Chapter 10, “Heron’s Formula,” from the Class 9 NCERT Mathematics textbook. It involves using Heron’s Formula to determine the areas of triangles and quadrilaterals, not Probability. Answer according to your understanding of the chapter.
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