Class 12 Physics
CBSE and UP Board
Electromagnetic Waves
Chapter-8 Exercise 8.7
NCERT Solutions for Class 12 Physics Chapter 8 Question 7
The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is Bo = 510 nT. What is the amplitude of the electric field part of the wave?
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Amplitude of magnetic field of an electromagnetic wave in a vacuum,
Bo = 510 nT = 510 x 10⁻9T
Speed of light in a vacuum, c = 3 x 108 m/s
Amplitude of electric field of the electromagnetic wave is given by the relation,
E = cBo
= 3 x 108x 510 x 10⁻9= 153 N/C
Therefore, the electric field part of the wave is 153 N/C.