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Ashok0210
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Asked: 2021-03-21T03:52:20+00:00 In:

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is Bo = 510 nT. What is the amplitude of the electric field part of the wave?

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Class 12 Physics
CBSE and UP Board
Electromagnetic Waves
Chapter-8 Exercise 8.7
NCERT Solutions for Class 12 Physics Chapter 8 Question 7

2020-2021cbse and up boardclass 12 chapter-8 physicsclass 12 physicsncert class 12 electromagnetic waves
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      Amplitude of magnetic field of an electromagnetic wave in a vacuum,
      Bo = 510 nT = 510 x 10⁻9T
      Speed of light in a vacuum, c = 3 x 108 m/s
      Amplitude of electric field of the electromagnetic wave is given by the relation,
      E = cBo
      = 3 x 108x 510 x 10⁻9= 153 N/C
      Therefore, the electric field part of the wave is 153 N/C.

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