Set up equations and solve them to find the unknown numbers in the following cases: (a) Add 4 to eight times a number; you get 60. (b) One-fifth of a number minus 4 gives 3.

(a) Let the number be x.
According to the question, 8x + 4 = 60
⇒ 8x=60-4
⇒ 8x = 56
⇒ x = 56/8
⇒ x = 7

(b) Let the number be y.
According to the question, y/5 – 4 = 3
⇒ y/5 = 3+4
⇒ y/5 = 7
⇒ y = 7×5
⇒ y = 35

Class 7 Maths Chapter 4 Exercise 4.4

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