(i) 8?

(ii)A student argues that ‘there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability 1/11. Do you agree with this argument? Justify your answer.

Math’s NCERT Class 10 Chapter 15 probability

Page No. 310

Exercise 15.1

Question No. 22

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(i) It can be observed that,

To get the sum as 2, possible outcomes =(1, 1)

To get the sum as 3, possible outcomes = (2,1) and (1, 2)

To get the sum as 4, possible outcomes = (3, 1), (1, 3), (2, 2)

To get the sum as 5, possible outcomes = (4, 1), (1, 4), (2, 3), (3, 2)

To get the sum as 6, possible outcomes = (5, 1), (1, 5), (2, 4). (4, 2), (3, 3)

To get the sum as 7, possible outcomes (6, 1). (1, 6), (2, 5), (5, 2), (3, 4), (4, 3)

To get the sum as 8, possible outcomes = (6, 2), (2, 6),. (3, 5), (5, 3), (4, 4)

To get the sum as 9, possible outcomes (3, 6), (6, 3), (4, 5), (5, 4)

To get the sum as 10, possible outcomes = (4, 6), (6, 4), (5, 5)

To get the sum as 11, possible outcomes = (5, 6). (6, 5)

To get the sum as 12, possible outcomes [6. 6)