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One of the two digits of a two-digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?

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NCERT Solutions for Class 8 Mathematics Chapter 2
Important NCERT Questions
Linear Equations in one Variable Chapter 2 Exercise 2.4
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 4

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1 Answer

  1. Let the unit place digit of a two-digit number be x.
    Therefore, the tens place digit = 3x
    2-digit number = 10 x tens place digit + unit place digit
    Original number = 10 x 3x + x =30x + x = 31x
    According to the question, New number + Original number = 88
    ⇒ 10x+3x+31x=88 ⇒ 44x=88 ⇒ x=88/44=2
    Hence, the 2-digit number = 31x=31X2=62

    Class 8 Maths Chapter 2 Exercise 2.4 Solution in Video

    for more answers vist to:
    https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-2/

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