Class 12 Physics
CBSE and UP Board
Alternating Current
Chapter-7 Exercise 7.6
NCERT Solutions for Class 12 Physics Chapter 7 Question 6
Obtain the resonant frequency ωr of a series LCR circuit with L = 2.0 H, C = 32μF and R = 10 Ω. What is the Q-value of this circuit?
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Inductance, L = 2.0 H
Capacitance, C = 32 μF = 32 x 10-6 F
Resistance, R = 10Ω
Resonant frequency is given by the relation,
ωr= 1/ √ (LC) = 1/ √ (2 x 32 x 10-6 ) = 1/(8 x 10⁻³ ) = 125 rad/s
Now ,Q-value of the circuit is given as :
Q = 1/R√ (L/C) = (1/10) x √[2/(32 x 10-6 ) ]
= 1/(10 x 4 x 10⁻³ ) = 25
Hence, the Q-Value of this circuit is 25.