Let f(x) = √1 + x², then
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Choice (b) is correct.
We have, f(x) = √1 + x²
f(y) = √1 + y² and f(xy) = √1 + (xy)² = √1 + x²y²
f(x).f(y) = √1 + x². √1 + y² = √1 + x² + y² + x²y²
√1+ x²y² ≤ √1 + x² + y² + x²y²
f(xy) ≤ f(x)f(y)
This question related to Chapter 2 maths Class 11th NCERT. From the Chapter 2: Relations and Functions. Give answer according to your understanding.
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