Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.

Given: BC = 48 m, CD = 17 m, AD = 40 m and perimeter = 120 m
∵ Perimeter of trapezium ABCD = AB + BC + CD + DA
⇒ 120 = AB + 48 + 17 + 40 ⇒ 120 = AB = 105
⇒ AB = 120 – 105 = 15 m
Now Area of the field = 1/2x(BC+AD)xAB
= 1/2 x (48+40)x15=1/2x88x15=660m²
Hence, area of the field ABCD is 660 m²

Class 8 Maths Chapter 11 Exercise 11.2 Solution in Video

for more answers vist to:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/chapter-11/