In Question 2, if 1 part of a red pigment requires 75 mL of base, how much red pigment should we mix with 1800 mL of base?

Let the parts of red pigment mix with 1800 mL base be x.

Parts of red pigment 1 x
Parts of base 75 1800
Since it is in direct proportion.
∴ 1/75 = x/1800 ⇒ 75Xx=1×1800 ⇒ x= 1×1800/75=24
Hence, with base 1800 mL, 24 parts red pigment should be mixed.

Class 8 Maths Chapter 11 Exercise 13.1 Solution in Video

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