Please provide me solution for this question and video explanation for better understanding.

NCERT class 10 chapter 12

Page No. 236

Exercise 12.3

Question No. 9

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Radius of smaller circle = 7/2 cm

Area of smaller circle = πr² = π(7/2)² = 22/7 × 7/2 × 7/2 = 77/2 cm²

Radius of larger circle = 7 cm

Area of semicircle AECFB

= 1/2 × πr² = π(7)² = 1/2 × 22/7 7 × 7 = 77 cm²

Area of triangle ACB

= 1/2 × AB × OC = 1/2 × 14 × 7 = 49 cm²

Area of Shaded Region

= Area of smaller circle + Area of semicircle AECFB – Area of triangle ACB

= (77/2 + 77 – 49) cm² = (38.5 + 28) cm² = 66.5 cm²

Here you can see the video explanation of this question for better understanding😄👇