Semicircles have diameter 2, radius 1. Perimeter consists of 4 full semicircular arcs totaling 4 x (pi x 1) = 4pi units. Flower area equals 4 semicircles minus the square: 2pi – 4 units².
In Fig. 6.50, four semicircles have been drawn within the given square whose side is 2 units. The centres of these semicircles are the midpoints of the sides. They create a 4-petalled flower (shown in blue). Find the perimeter and the area of this flower.
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The square has side s = 2 units, so its area is 2² = 4 units².
Each semicircle is drawn on a side of length 2 as diameter, giving radius r = 1 unit.
Perimeter of flower:
The boundary of the 4 petals is made up of 4 semicircular arcs of radius 1.
Total perimeter = 4 x (pi x r) = 4 x pi x 1 = 4pi units (approximately 12.57 units).
Area of flower:
The four semicircles overlap to create the 4 petals.
Sum of areas of 4 semicircles = 4 x (1/2 x pi x 1²) = 2pi units².
Area of flower = Sum of 4 semicircles – Area of square = 2pi – 4 units² (approximately 2.28 units²).
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/