In Fig. 10.11, if TP and TQ are the two tangents to a circle with Centre O so that angle POQ = 110°, then angle PTQ is equal to

Given: TQ and TP are two tangents of the circle.
We know that the radius is perpendicular to tangent. Therefore, OP ⊥TP and OQ TQ.
⇒ ∠OPT = 90° and ∠OQT = 90°
In quadrilaterral POQT, OQT + OQT + PTQ = 360°
⇒ 90° + 110° + 90° + ∠PTQ = 360°
⇒ ∠PTQ = 360° – 290° = 70
Hence, the option (B) is correct.