Class 12 Physics
CBSE and UP Board
Wave Optics
Chapter-10 Exercise 10.16
NCERT Solutions for Class 12 Physics Chapter 10 Question-16
Additional Exercise
In double-slit experiment using light of wavelength 600 nm, the angular width of a fringe formed on a distant screen is 0.1º. What is the spacing between the two slits?
Share
Wavelength of light used, λ = 6000 nm = 600 x 10-9 m
Angular width of fringe, 0 = 0.1° = 0.1 x π/180 = 3.14 /1800 rad
Angular width of a fringe is related to slit spacing (d) as: 0 = λ /d => d = λ/0
=> d = (600 x 10-9) /(3.14/1800) = 3.44 x 10⁻4 m
Therefore, the spacing between the slits is 3.44 x 10⁻4 m.