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In a potentiometer of wire length l, a cell of emf V is balanced at a length l/3 from the positive end of the wire. For another cell of emf 1-5 V, the balancing length becomes
In a potentiometer, the balancing length is proportional to the emf of the cell. Given V balances at l/3, for a cell of emf 1.5V, the new balancing length is
(1.5V/V) × (l/3) = 2l/3. Answer: (d) 2l/3.
Class 12th Science Physics NCERT MCQ Questions
NCERT Books MCQ Questions Session 2024-2025.
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