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In a potentiometer of wire length /, a cell of emf V is balanced at a length U3 from the positive end of the wire. For another cell of emf 1-5 V, the balancing length becomes
In a potentiometer, emf ∝ balancing length. Given v/1.5V = U3/Lx , solving for Lx gives Lx = L/3. Answer: (c) l/3.
Class 12th Science Physics NCERT MCQ Questions
NCERT Books MCQ Questions Session 2024-2025.
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