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In a meter bridge experiment, resistance box (with R = 2 n) is connected in the left gap and the unknown resistance S in the right gap. If the balancing length be 40 cm, calculate the value of S
In a meter bridge, the balancing condition is R / S = L / (100 – L). Given R = 2 Ω and L = 40 cm, we get 2 / S = 40 / 60. Solving for S, S = 3 Ω.
Correct answer: (b) 3 Ω.
Class 12th Science Physics NCERT MCQ Questions
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