As written, this statement appears inconsistent with the figure/text. Since each chord is perpendicular to diameter AB, its midpoint lies on AB. Therefore, the segment joining the two midpoints lies along AB, so it is parallel to AB, not perpendicular.
In a circle, two chords CC’ and DD’ are drawn perpendicular to a diameter AB. Prove that the segment MM’ joining the midpoints of the chords CD and C’D’ is perpendicular to AB.
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There appears to be a problem in the question as shown in the screenshot. If the two chords CC’ and DD’ are each drawn perpendicular to the diameter AB, then the perpendicular from the centre to each chord bisects that chord. Since AB passes through the centre, the midpoints M and M’ of these chords lie on AB. Therefore, the segment MM’ joining the midpoints lies along AB. Hence, MM’ is parallel to AB, not perpendicular to AB. So the printed statement cannot be proved as written.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/