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Home/ Questions/Q 7164
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Ashok0210
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Ashok0210
Asked: February 13, 20212021-02-13T07:23:04+00:00 2021-02-13T07:23:04+00:00In: Class 12 Physics

In a certain region of space, electric field is along the z-direction throughout. The magnitude of electric field is, however, not constant but increases uniformly along the positive z-direction, at the rate of 10⁵ NC⁻¹ per metre. What are the force and torque experienced by a system having a total dipole moment equal to 10⁻⁷ Cm in the negative z-direction ?

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Class-12th Physics, CBSE and UP Board
Electric Charges and Fields,
Chapter-1, Exercise -1, Additional Exercise, Q-1.27
NCERT Solutions for Class 12th Physics

2020-2021cbsechapter 1class 12 physicsclass 12thelectric charges and fieldsncertncert solutionsphysicsscience
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    1. Pritika2411
      2021-02-17T15:30:19+00:00Added an answer on February 17, 2021 at 3:30 pm

      Dipole moment of the system, p=q x dl =10⁻⁷Cm

      Rate of increase of electric field per unit length dE/dl =105 NC_1

      Force (F) experienced by the system is given by the relation,

      F = qE = q x (dE/dl) x dl = q x dl x (dE/dl) = p x (dE/dl)

      = —1(10⁻7 x 105 )= —10⁻2 N

      The force is -10-2 N in the negative z-direction i.e., opposite to the direction of electric field. Hence, the angle between electric field and dipole moment is 180°.

      Torque (τ) is given by the relation, τ = pE sinl80° = 0

      Therefore, the torque experienced by the system is zero.

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