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In ΔABC, if ∠B = 90°, AB = 6 cm, and BC = 8 cm, then sin A equals:

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50% 6/10 ( 1 voter )
50%8/10 ( 1 voter )
0%3/4
0%4/3
Based On 2 Votes

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ΔABC represents a triangle with three vertices A, B, and C. It is a fundamental geometric shape with three sides and three angles. The sum of its interior angles is always 180°. Depending on side lengths and angles, ΔABC can be classified as scalene, isosceles, or equilateral.

Class 10 Maths Chapter 6 Triangles focuses on similarity and congruence of triangles. It covers theorems like the Pythagoras theorem and concepts of proportionality. Students learn to apply these properties in problem-solving and real-life situations. Mastering this chapter is essential for CBSE Exam 2024-25 and builds a strong foundation for higher mathematics and practical applications.

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1 Answer

  1. In ΔABC, given that ∠B = 90°, AB = 6 cm, and BC = 8 cm, we can determine sin A using the definition of sine in a right triangle.

    First, calculate the hypotenuse AC using the Pythagorean theorem:
    AC² = AB² + BC²
    AC² = 6² + 8²
    AC² = 36 + 64
    AC² = 100
    AC = √100 = 10 cm

    Now, recall that sin A is defined as the ratio of the length of the side opposite to ∠A (BC) to the hypotenuse (AC):
    sin A = (opposite side) / (hypotenuse)
    sin A = BC / AC
    sin A = 8 / 10

    Thus, the correct answer is 8/10.

    Click here for more:
    https://www.tiwariacademy.in/ncert-solutions-class-10-maths-chapter-6/

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