If triangle ABC is right angled at C, then the value of cos (A + B) is
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In a right-angled triangle ABC, with C as the right angle:
A + B = 90° (since A + B + C = 180° and C = 90°).
Thus, cos(A + B) = cos(90°) = 0.
This question related to Chapter 8 Mathematics Class 10th NCERT. From the Chapter 8 Introduction to Trigonometry. Give answer according to your understanding.
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