NCERT Solutions for Class 10 Maths Chapter 2
Important NCERT Questions
Polynomials
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 2.4
Page No:36
Questions No:1 Part:3
If the zeroes of the polynomial x³ – 3 x² + x + 1 are a – b, a, a + b, find a and b.
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We know that,
Sum of zeroes = -(Cofficient of x²)/Cofficient of x³)
Therefore,
(a – b) + a + (a + b) = (-(-3))/1
⇒ 3a = 3
⇒ a = 1
Product of zeroes = -(Constant term)/(Cofficient of x³)
Therefore,
(a – b)(a)(a + b) = -(1)/1
⇒ (1 – b)1(1 + b) = -1 [Because a = 1]
⇒ 1 – b² = – 1
⇒ b² = 2
⇒ b = +- √2
Hence, a = 1 and b = +- √2
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