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If the sum of the zeros of the quadratic polynomial ax² + bx + c is -4 and the product of the zeros is 3, then the polynomial is:

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Poll Results

37.5%x² + 4x + 3 ( 3 voters )
37.5%x² - 4x + 3 ( 3 voters )
12.5% x² + 4x - 3 ( 1 voter )
12.5%x² - 4x - 3 ( 1 voter )
Based On 8 Votes

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A quadratic polynomial is an algebraic expression of degree 2 written in the form ax^2 + bx + c where a b and c are constants and a is not equal to zero. It represents a parabola when graphed and its zeros are the solutions of the related quadratic equation. Understanding this concept is essential for solving real-life problems and higher-level mathematics.

Class 10 Maths Chapter 2 Polynomials focuses on understanding zeros and coefficients of polynomials along with division algorithms. It covers linear quadratic and cubic polynomials and their graphical representation. This chapter strengthens problem-solving skills for CBSE Exam 2024-25 and builds a foundation for advanced algebraic concepts ensuring clarity in mathematical relationships and applications in real-life situations.

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1 Answer

  1. Constructing a Quadratic Polynomial with Specific Zero Properties

    Step 1: Understanding Vieta’s Formulas
    For a quadratic polynomial ax² + bx + c with zeros p and q:
    – Sum of zeros: p + q = -b/a
    – Product of zeros: p * q = c/a

    Given Conditions:
    – Sum of zeros = -4
    – Product of zeros = 3

    Step 2: Analyzing the Coefficients
    Let’s consider a standard quadratic form: x² + 4x + c

    Checking Sum of Zeros:
    – p + q = -4
    – This means the coefficient of x must be -4

    Checking Product of Zeros:
    – p * q = 3
    – This means the constant term must be 3

    Step 3: Verification
    The polynomial becomes: x² – 4x + 3

    Mathematical Verification:
    Let’s find the zeros using the quadratic formula:
    x = [4 ± √(16 – 4(1)(3))] / 2(1)
    = [4 ± √(16 – 12)] / 2
    = [4 ± √4] / 2
    = [4 ± 2] / 2

    Zeros are:
    – p = (4 + 2)/2 = 3
    – q = (4 – 2)/2 = 1

    Checking Conditions:
    – Sum of zeros: 3 + 1 = 4 ✓
    – Product of zeros: 3 * 1 = 3 ✓

    Key Insights:
    – Vieta’s formulas provide a powerful way to relate
    zeros to polynomial coefficients
    – We can construct polynomials by understanding
    the relationships between zeros and coefficients

    Conclusion:
    The polynomial that satisfies the given conditions is x² – 4x + 3.

    Click here for more:
    https://www.tiwariacademy.in/ncert-solutions/class-10/maths/

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