If the roots of the quadratic equation x² – (a + 1)x + a = 0 are equal, then the value of a is:
The roots of a quadratic equation represent the x-values where the parabola intersects with the x-axis. A quadratic can have two real roots when it crosses the x-axis at two points or one real root when it touches the x-axis at exactly one point or no real roots when it never intersects the x-axis.
A quadratic equation follows the standard form ax² + bx + c = 0 where a not equal to zero. Students learn methods to find solutions including factorization square completion algebraic formula and graphical representation. Real-world applications involve finding areas distances speeds and projectile motion. The chapter explores the nature of roots based on discriminant and proves essential for higher mathematics concepts in polynomials and coordinate geometry. Students must master this fundamental topic for CBSE board examinations and future mathematical studies.
Given quadratic equation: x² – (a + 1)x + a = 0
For equal roots, discriminant should be zero:
b² – 4ac = 0
Here:
a = 1 (coefficient of x²)
b = -(a + 1)
c = a
Substituting in discriminant:
[-(a + 1)]² – 4(1)(a) = 0
(a + 1)² – 4a = 0
a² + 2a + 1 – 4a = 0
a² – 2a + 1 = 0
(a – 1)² = 0
Therefore:
a = 1
This can be verified by substituting a = 1 in original equation:
x² – 2x + 1 = 0
(x – 1)² = 0
x = 1 (repeated root)
Hence, 1 is the correct answer.
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