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If the equation kx² – 6x + 2 = 0 has equal roots, then the value of k is:

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25%-3 ( 1 voter )
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Equal roots occur when the discriminant (b² – 4ac) equals zero in a quadratic equation. This makes both roots identical meaning the parabola touches the x-axis at exactly one point. The value of both roots can be found using -b/2a and this point is called the vertex of the parabola.

A quadratic equation takes the form ax² + bx + c = 0 where a is not equal to zero. These equations have vital applications in physics business and engineering. The solutions or roots can be found using factorization methods perfect square method or quadratic formula (-b ± √(b² – 4ac))/2a.
A quadratic equation can have real and distinct roots real and equal roots or no real roots based on the discriminant (b² – 4ac). Understanding graphical representation helps visualize the nature of roots as intersections with x-axis.

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2 Answers

  1. For equal roots, discriminant must be zero:
    b² – 4ac = 0

    Given equation: kx² – 6x + 2 = 0

    Here:
    a = k
    b = -6
    c = 2

    Putting in discriminant:
    (-6)² – 4(k)(2) = 0

    36 – 8k = 0

    8k = 36

    k = 9

    To check:
    When k = 9:
    9x² – 6x + 2 = 0
    Using quadratic formula:
    x = [6 ± √(36 – 72)]/18
    x = [6 ± 0]/18
    x = 1/3 (repeated root)

    Therefore, 9 is the answer.

    Click here for more:
    https://www.tiwariacademy.in/ncert-solutions/class-10/maths/

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