If the distance between the points (4, p) and (1, 0) is 5, then the value of p is
Enhance your Class 10th Maths preparation with NCERT solutions and MCQ-based questions from Chapter 7 Coordinate Geometry. Dive into exercise questions short-answer problems and clear explanations to grasp key concepts like distance formula section formula and area of a triangle. These resources are designed as per the CBSE syllabus for effective exam preparation. Consistent practice will refine your problem-solving skills and boost your confidence for board exams. Utilize step-by-step solutions and revision notes created to guide students toward achieving excellent results. Start practicing now!
Share
To solve for the value of p, we use the distance formula between two points (x₁, y₁) and (x₂, y₂):
d = √((x₂ – x₁)² + (y₂ – y₁)²)
Here, the points are (4, p) and (1, 0), and the distance is given as 5. Substituting into the formula:
5 = √((1 – 4)² + (0 – p)²)
Simplify the terms inside the square root:
5 = √((-3)² + (-p)²)
5 = √(9 + p²)
Square both sides to eliminate the square root:
5² = 9 + p²
25 = 9 + p²
Rearrange the equation to isolate p²:
p² = 25 – 9
p² = 16
Take the square root of both sides:
p = ±√16
p = ±4
Thus, the value of p can be either +4 or -4.
The correct answer is:
b) ±4
This question related to Chapter 7 Mathematics Class 10th NCERT. From the Chapter 7 Coordinate Geometry. Give answer according to your understanding.
For more please visit here:
https://www.tiwariacademy.in/ncert-solutions-class-10-maths-chapter-7/