(i) 16² = 256 and 17² = 289 ⇒ 289 – 256 – 1 = 32 numbers.
(ii) 99² = 9801 and 100² = 10000 ⇒ 10000 – 9801 – 1 = 198 numbers between them.
Class 8 Mathematics Textbook Chapter 1 A Square and A Cube question answer
Class 8 Mathematics Chapter 1 A Square and A Cube solutions
(i) 16² = 256, 17² = 289. So, numbers between them = 289 – 256 – 1 = 32.
(ii) 99² = 9801, 100² = 10000. So, numbers between = 10000 – 9801 – 1 = 198.
In general, numbers between n² and (n+1)² are 2n.
Hence, between 16² and 17² → 32 numbers; between 99² and 100² → 198 numbers.
For more NCERT Solutions for Class 8 Mathematics Ganita Prakash Chapter 1 A Square and A Cube Extra Questions & Answer:
https://www.tiwariacademy.com/ncert-solutions/class-8/maths/ganita-prakash-chapter-1/