How many 176 ohm resistors (in parallel) are required to carry 5 A on a 220 V line?

Let the total number of resistors be x.
Given that: Current I = 5 A and Potential Difference V = 220 V
According to Ohm’s law, V = IR
⟹𝑅=𝑉/𝐼=220/5=44 Ω
Now for x number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is 44 Ω.
1/44= 1/176 +1/176 +1/176 + 1/176 +..𝑡𝑜 𝑥 𝑡𝑖𝑚𝑒𝑠 ⟹ 1/44=𝑥/176 ⟹𝑥=176/44=4
Therefore, 4 resistors of 176 Ω are required to draw the given amount of current.

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