Consider changing dimensions from (l, w, h) to (l’, w’, h’). One valid example: an initial cuboid of dimensions 1 × 1 × 8 has V = 8 and SA = 34. Rescaling dimensions to 0.25 × 2 × 8 gives halved volume V’ = 4 and doubled surface area SA’ = 68.
Class 9 Ganita Manjari part 2 Chapter 14 end of chapter exercise Solutions
Class 9 Ganita Manjari Part II Chapter 14 Page 146 Question Answer
Let original dimensions be l, w, h with volume V = lwh and total surface area S = 2(lw + wh + hl). If transformed to new dimensions l’, w’, h’, we require V’ = V/2 and S’ = 2S. For instance, start with a 1 cm × 1 cm × 8 cm cuboid (V = 8 cm³, S = 34 cm²). Changing dimensions to 0.25 cm × 2 cm × 8 cm yields new volume V’ = 4 cm³ (halved) and new surface area S’ = 2(0.5 + 16 + 2) = 68 cm² (doubled).
For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 14 Math of Space: Surface Area and Volume Question Answer (2026-27)
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-14/