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Anwesha Patel
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Asked: 2023-02-21T08:43:41+00:00 In:

From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown in Figure. Find the area of the remaining portion of the square.

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From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown in Figure. Find the area of the remaining portion of the square.

I need a video solution for this given question which is from ncert class 10 math’s chapter 12.
NCERT Class 10 maths Chapter 12
Page No. 235
Exercise 12.3
Question No. 5

chapter 12class 10ncert math
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      From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown in Figure. Find the area of the remaining portion of the square.

      Radius of each quadrant = 1 cm
      Area of each quadrant
      = 90°/360° × πr² = 1/4 × π(1)² = 1/4 × 22/7 × 1 × 1 = 11/14 cm²
      Area of circle
      = πr² = π(1)² = 22/7 × 1 × 1 = 22/7 cm²
      Area of square = (Side)² = (4)² = 16 cm²
      Area of shaded region = Area of square Area of circle – Area of 4 quadrants
      16 – 22/7 – 4 × 11/14 = 16 – 22/7 – 22/7 = (112 – 44)/7 = 68/7 cm²

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