Asked: 2025-02-14T08:12:07+00:002025-02-14T08:12:07+00:00In: Class 12 Physics
Four charges + 8Q – 3 Q + 5 Q and – 10 Q are kept inside a closed surface. What will be the outgoing flux through the surface,
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According to Gauss’s Law, the total electric flux (Φ) through a closed surface is given by:
Φ = Qenclosed/ε0
where Qₑ is the total charge enclosed within the surface.
The total charge enclosed is:
Q enclosed = (+8Q) + (-3Q) + (+5Q) + (-10Q)
Q enclosed = 8Q – 3Q + 5Q – 10Q = 0
Since the total enclosed charge is zero, the outgoing flux is also zero.
Thus, the correct answer is (b) 0 V·m.
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