Following table shows the points of each player scored in four games: Now answer the following questions: (i) Find the mean to determine A’s average number of points scored per game. (ii) To find the mean number of points per game for C, would you divide the total points by 3 or 47? Why? (iii) B played in all the four games. How would you find the mean? (iv) Who is the best performer?

(i) Mean of player A = Sum of scores by A / No. of games played by A
= 14+16+10+10/4 = 50/4 = 12.5

(ii) We should divide the total points by 3 because player C played only three
games.

(iii) Player B played in all the four games.
∴ Mean of player B = Sum of scores by B/No. of games played by B
= 0+8+6+4/4 = 18/4 = 4.5

(iv) To find the best performer, we should know the mean of all players.
Mena of player A = 12.5
Mean of player B = 4.5
Mean of player C = 8+11+3/3 = 32/3 = 10.67
Therefore, on comparing means of all players, player A is the best performer.

Class 7 Maths Chapter 3 Exercise 3.1

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