Let their present ages be x and y. Then x – 5 = 3(y – 5) and x + 10 = 2(y + 10). Simplifying yields x – 3y = -10 and x – 2y = 10. Solving gives y = 20 and x = 50 years.
Ganita Manjari Part 2 chapter 13 question answer
Ganita Manjari Part 2 chapter 13 Two Variables, One Line solutions
Let the present ages of Nuri and Sonu be x and y years respectively. Five years ago, (x – 5) = 3(y – 5), which simplifies to x – 3y = -10. Ten years later, (x + 10) = 2(y + 10), which simplifies to x – 2y = 10. Subtracting the first equation from the second eliminates x and gives y = 20. Substituting y = 20 yields x = 50. Therefore, Nuri is 50 and Sonu is 20 years old.
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