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Rajni Kothari
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Asked: 2020-12-28T03:45:16+00:00 In:

Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. x² – 2x – 8.

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NCERT Solutions for Class 10 Maths Chapter 2
Important NCERT Questions
Polynomials
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 2.2
Page No:33
Questions No:1 Part:1

2020-2021cbsechapter 2class10mathematicsncertpolynomials
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    2 Answers

    1. Best Answer

      x² – 2x – 8
      = x² – 4x + 2x – 8
      = x(x – 4) + 2(x – 4)
      = (x + 2)(x – 4)
      The value of x² – 2x – 8 is zero if x + 2 = 0 or x – 4 = 0
      x = -2 or x = 4
      Therefore, the zeroes of x² – 2x – 8 are -2 and 4. Now
      Sum of zeroes = -2 + 4 = 2 = -(-2)/1 =-(Cofficient of x)/(Cofficient of x²)
      Product of zeroes = (-2) x 4 = -8 =-8/1 = (Cofficient term)/Cofficient of x²)

      Video Explanation 👇

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    2. Get Hindi Medium and English Medium NCERT Solution for Class 10 Maths to download.
      Please follow the link to visit website for first and second term exams solutions.
      https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-2/

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