Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. x² – 2x – 8.

x² – 2x – 8
= x² – 4x + 2x – 8
= x(x – 4) + 2(x – 4)
= (x + 2)(x – 4)
The value of x² – 2x – 8 is zero if x + 2 = 0 or x – 4 = 0
x = -2 or x = 4
Therefore, the zeroes of x² – 2x – 8 are -2 and 4. Now
Sum of zeroes = -2 + 4 = 2 = -(-2)/1 =-(Cofficient of x)/(Cofficient of x²)
Product of zeroes = (-2) x 4 = -8 =-8/1 = (Cofficient term)/Cofficient of x²)

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