Rajni Kothari
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Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients. 6x² – 3 – 7x.

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NCERT Solutions for Class 10 Maths Chapter 2
Important NCERT Questions
Polynomials
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 2.2
Page No:33
Questions No:1 Part:3

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  1. Get Hindi Medium and English Medium NCERT Solution for Class 10 Maths to download.
    Please follow the link to visit website for first and second term exams solutions.
    https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-2/

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  2. 6x² – 3 – 7x
    = 6x² – 7x – 3
    = 6x² – 9x + 2x -3
    = 3x(2x – 3) + 1(2x -3)
    = (3x +1)(2x -3)
    The value of 6x² – 7x – 3 is zero if 3x + 1 = 0 or 2x -3 = 0.
    ⇒ x = -1/3 or x = 3/2,
    Therefore, the zeroes of 6x² – 7x – 3 are -1/3 and 3/2.
    Now, Sum of zeroes = -1/3 + 3/2 = (-2 + 9)/6 = 7/6 = -(7)/6 = -(Cofficient of x)/Cofficient of x²
    Product of zeroes = (-1/3) x 3/2 = -1/2 = (-3)/6 = Constant term/Cofficient of x².

    See here 😎

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