(i) Square side 14 cm gives 4 semicircles of diameter 14 cm; each petal side is a quarter circle of radius 7 cm, totaling 8 x (π x 7 / 2) = 88 cm. (ii) Hexagon side 42 cm gives 12 arcs of 60° with radius 42 cm, totaling 12 x (2 x π x 42 x 60/360) = 528 cm.
Find the total perimeter of all the petals in each of the given flowers. (i) Fig. 6.15A: The centres of the arcs are the midpoints of the sides of the square. (ii) Fig. 6.15B: The centres of the arcs are the vertices of the hexagon.
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(i) In Fig. 6.15A, the 4 petals are formed by 8 quarter-circle arcs of radius r = 14 / 2 = 7 cm.
Length of one arc = (1/4) x 2 x π x r = (1/4) x 2 x (22/7) x 7 = 11 cm.
Total perimeter of 4 petals (8 arcs) = 8 x 11 = 88 cm.
(ii) In Fig. 6.15B, the 6 petals are formed by 12 arcs with centres at the vertices of a regular hexagon of side 42 cm (central angle = 60°, radius r = 42 cm).
Length of one arc = 2 x (22/7) x 42 x (60/360) = 264 x (1/6) = 44 cm.
Total perimeter of 6 petals (12 arcs) = 12 x 44 = 528 cm.
For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)
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