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Find the sum of the following APs: –37, –33, –29, . . ., to 12 terms.

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Verifying the mathematical identity or testing the mathematical theorem.
How the equation behaves under different conditions.
CBSE Board and UP Board and Others state Board.
Important Arithmetic Progression Solutions for Class 10th.

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1 Answer

  1. A.P. : 37, 33, 29, …
    Here, a = -37 and d = 33 – (-37) = 4.
    The sum of n terms of an AP is Given by
    S_n = n/2[2a + (n -1)d]
    ⇒ S₁₂ = 12/2[2(-37) + (12 -1)(4)]
    ⇒ S₁₂ = 6[- 74 + 44] = – 180

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