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Find the smallest 4-digit number which is divisible by 18, 24 and 32.

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NCERT Solutions for Class 6 Maths Chapter 3
Important NCERT Questions
Playing With Numbers Chapter 3 Exercise 3.7
NCERT Books for Session 2022-2023
CBSE Board
Questions No: 9

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1 Answer

  1. Hints:-

    L.C.M. of 18, 24 and 32 = 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288
    The smallest four-digit number = 1000

    Therefore, the required number is 1000 + (288 – 136) = 1152.

    https://www.tiwariacademy.com/ncert-solutions/class-6/maths/chapter-3/

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