Remainders obtained when each of the following numbers is divided by 10, 5, 2.
- 78: Rem. by 10: 8, by 5: 3, by 2: 0
- 99: Rem. by 10: 9, by 5: 4, by 2: 1
- 173: Rem. by 10: 3, by 5: 3, by 2: 1
Class 6 Mathematics Chapter 5 Prime Time question answer
Class 6 NCERT Ganita Prakash Chapter 5 Prime Time
Remainders obtained when each of the following numbers is divided by 10, 5, 2
• 572: Rem. by 10: 2, by 5: 2, by 2: 0
• 980: Rem. by 10: 0, by 5: 0, by 2: 0
• 1111: Rem. by 10: 1, by 5: 1, by 2: 1
• 2345: Rem. by 10: 5, by 5: 0, by 2: 1
Each remainder is calculated by direct division and finding the leftover.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/